Yes, that's straightforward with the exception of the slip built in. Do you always factor in a 12% slip?
Also, none of that takes into account prop size, which I assume will increase the torque of the motor. Torque x rpm = power, so given an efficient rpm for a motor and the power rating of the motor and controller, I can figure out the available torque the motor can put out. If I could relate that to the prop size then I could calculate the optimal prop size. Or does it not work quite like that?
Thanks,
-keith
--- On Thu, 5/3/12, Robert Lemke <
robert-lemke@att.net> wrote:
The Parsun will be a 10 hp, not 10 Kw. Determine prop shaft rpm and pitch for speed desired. If shaft speed is say 2200 rpm X 4" pitch = 8800" per minute X 60 = 528,000 inches per hour / 12 = 44,000 feet per hour / 5280 = 8.33 mph X 0.88 slip = 7.33 mph, easy, huh?
Bob
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