Volts x amps = power in watts.
2.5 kn - 7 x 48 = 336 W
4.9 kn - 64 x 48 = 3072 W
5.4 kn - 90 x 48 = 4320 W
5.8 kn - 122 x 48 = 5856 W
5.9 kn - 141 x 48 = 6768 W
So, it seems obvious something around 4 kW steady state (continuous duty) is the "right" minimax choice, with extra pwr being a personal preference, and not practically useful, in general.
Half a kn speed = 50% morepower wasted, for no real meaningful result.
Note that I asked for the volts because if the system was, say, 24 V, then the power needed would have been half.
48 volts
-------- Original message --------From: "Hannu Venermo gcode.fi@gmail.com [electricboats]" <electricboats@yahoogroups.com>Date: 1/24/2016 1:16 AM (GMT-06:00)Subject: Re: [Electric Boats] Re: 12V DC -> 120V AC vs. 48V DC -> 120V AC
What the voltage, please ?
Here is the profomance data for my Pearson P 30 with Electric Yacht 10 kw. System and a 3 blade prop
Speed. Knots RPM. Amps. L mrtTemp2.5. 774. 7. 783. 1079. 17. 803.8. 1305. 28. 804..3. 1505. 42. 844.9. 1754. 64. 865.4. 1926. 90. 935.8. 2115. 122. 1005.9. 2193. 141. 107
-- -hanermo (cnc designs)
Posted by: Hannu Venermo <gcode.fi@gmail.com>
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